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Laws Of Motion

Question
CBSEENPH11020663

Two stone of masses m and 2m are whirled in horizontal circles, the heavier one in a radius r/2 and the lighter one in radius r. The tangential speed of lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is

  • 2

  • 3

  • 4

  • 1

Solution

A.

2

Given, that two stones of masses m and 2m are whirled in horizontal circles, the heavier one in a radius r/2 and lighter one in radius r as shown in a figure.


As lighter stone is n times that of the value of heavier stone when they experience same centripetal forces, we get
(Fc)heavier = (Fc)lighter
fraction numerator 2 straight m left parenthesis straight v right parenthesis squared over denominator straight r divided by 2 end fraction space equals space fraction numerator straight m left parenthesis nv right parenthesis squared over denominator 2 end fraction

straight n squared space equals space 4

straight n space equals space 2