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Mechanical Properties Of Fluids

Question
CBSEENPH11020532
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The two ends of a metal rod are maintained at temperatures 100o C and 110o C. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200o C and 210o C, the rate of heat flow will be

  • 44.0 J/s

  • 16.8 J/s

  • 8.0 J/s

  • 4.0 J/s

Solution

D.

4.0 J/s

Here, Δ T1 = 110-100 = 10o C 
dQ subscript 1 over dt space equals space 4 straight J divided by straight s increment straight T subscript 2 space equals space 210 minus 200 space equals space 10 to the power of straight o space straight C dQ subscript 2 over dt space equals space ?
As the rate of heat flow is directly proportional to the temperature difference and the temperature difference in both the cases is same i.e. 10o C. So, the same rate of heat will flow in the second case. 
Hence,
dQ over dt space equals space 4 straight J divided by straight s

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