Question
A particle of unit mass undergoes one-dimensional motion such that its velocity according to
V(x) = βx-2n where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x is given by
-
-2nβ2 x-2n-1
-
-2nβ2 x-4n-1
-
-2β x-2n+1
-
-2nβ2e-4n+1
Solution
B.
-2nβ2 x-4n-1
Given, v = βx-2n