Question
From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc, about a perpendicular axis, passing through the centre?
-
13 MR2/32
-
11MR2/32
-
9MR2/32
-
15MR2/32
Solution
A.
13 MR2/32
Illustrating the above figure,
As given in the above fig.,
Moment of Inertia of the disc, I = Iremain + I(R/2)
Now, using the values, we get
That is,
Iremain =
That is,
Iremain =
