-->

Mechanical Properties Of Fluids

Question
CBSEENPH11020585

A thermodynamic system undergoes cyclic process ABCDA as shown in the figure. The work done by the system in the cycle is:

  • po Vo

  • 2 po Vo

  • fraction numerator straight p subscript straight o space straight V subscript straight o over denominator 2 end fraction
  • zero

Solution

D.

zero

Work done in the cyclic process = Area bound by the closed configuration
= Area of closed configuration
equals space open curly brackets 2 space open square brackets 1 half left parenthesis straight V subscript straight o divided by 2 right parenthesis space straight x space straight p subscript straight o close square brackets space plus space minus 2 open square brackets 1 half left parenthesis straight V subscript straight o divided by 2 right parenthesis space straight p subscript straight o close square brackets close curly brackets

equals space zero