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Motion In Straight Line

Question
CBSEENPH11020583

The motion of a particle along a straight line is described by equation
 x=8+12 t -t3

where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is

  • 24 ms-2

  • zero

  • 6 ms-2

  • 12 ms-2

Solution

D.

12 ms-2

Given :  x=8+12 t -t3
We space know space straight v space equals space dx over dt
and space space straight a equals dv over dt
So comma space straight v equals 12 minus 3 straight t squared
and space straight a equals negative 6 straight t
At space straight t space equals space 2 straight s
space straight v equals space 0 space and space straight a space equals space minus 6 straight t
straight t space equals space 2 straight s
space straight a space equals space minus space 12 straight m divided by straight s squared space
so space retardation space of space the space particle space equals space 12 straight m divided by straight s squared