Sponsor Area

Mechanical Properties Of Fluids

Question
CBSEENPH11020582

Certain quantity of water cools from 70o C to 60o C in the first 5 min and to 54o  C in the next 5 min. The temperature of the surroundings is,

  • 45o C

  • 20o C

  • 42o C

  • 10o C

Solution

A.

45o C

Assume, the temperature of the surrounding be to C.
Case 1:
fraction numerator 70 space minus 60 over denominator 5 space min end fraction space equals space K space left parenthesis 65 to the power of o space C space minus space t to the power of o space C right parenthesis
The average of 70 and 60 is 65.
fraction numerator 10 over denominator 5 space min end fraction space equals space K space left parenthesis 65 to the power of o space C space minus space t to the power of o space C right parenthesis         ... (i)
Case 2:
fraction numerator 60 space minus space 54 over denominator 5 space min end fraction space equals space K space left parenthesis 57 space minus space t right parenthesis             ... (ii)
Dividing equations (i) and (ii), we get
10 over 6 equals fraction numerator left parenthesis 65 minus t right parenthesis over denominator left parenthesis 57 space minus t right parenthesis end fraction
On solving, we get
Temperature, t = 45o C