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Laws Of Motion

Question
CBSEENPH11020580
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A car of mass 1000 kg negotiates a banked curve of radius 90m on a frictionless road. If the banking angle is 45o, the speed of the car is 

  • 20 ms-1

  • 30ms-1

  • 5 ms-1

  • 10 ms-1

Solution

B.

30ms-1

The angle of banking
tan space straight theta space equals space straight v squared over rg Given comma space straight theta space equals space 45 to the power of straight o comma space straight r equals space 90 space straight m space and space straight g space equals space 10 space straight m divided by straight s squared tan space 45 to the power of straight o space equals space fraction numerator straight v squared over denominator 90 space straight x space 10 end fraction straight v space equals space square root of 90 space straight x 10 space straight x space tan space 45 to the power of straight o end root speed space of space car space straight v space equals space 30 space straight m divided by straight s

Some More Questions From Laws of Motion Chapter

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