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Mechanical Properties Of Fluids

Question

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If the radius of a star is R and it acts as a black body, what would be the temperature of the star, in which the rate of energy production is Q?

Q/4πR²σ

(Q/4πR²σ)^-1/2

(4πR²Q/σ)^1/4

(Q/4πR²σ)^1/4

Solution

D.

(Q/4πR²σ)^1/4

From Stefan' law
E =σT⁴
so, the rate energy production
Q=E x A

Q = σT⁴ x 4πR²
Temperature of star

straight T space equals open parentheses fraction numerator straight Q over denominator 4 πR squared straight sigma end fraction close parentheses to the power of 1 divided by 4 end exponent

Some More Questions From Mechanical Properties of Fluids Chapter

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