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Laws Of Motion

Question
CBSEENPH11020565

A system consists of three masses m1, m2 and m3 connected by a string passing over a pulley P. The mass m1 hangs freely and m2 and m3 are on a rough horizontal table (the coefficient of friction= straight mu). the pulley is frictionless and of negligible mass. The downward acceleration of mass m1 is,

  • fraction numerator straight g space left parenthesis 1 minus gμ right parenthesis over denominator straight g end fraction
  • fraction numerator 2 gμ over denominator 3 end fraction
  • fraction numerator straight g space left parenthesis 1 minus 2 straight mu right parenthesis over denominator 3 end fraction
  • fraction numerator straight g left parenthesis 1 minus 2 straight mu right parenthesis over denominator 2 end fraction

Solution

C.

fraction numerator straight g space left parenthesis 1 minus 2 straight mu right parenthesis over denominator 3 end fraction

First of all consider the forces on the blocks,

For the 1st block,
mg - T1 = m x a        ... (i)
Let us consider second and third block as a system,
Then,
T12 μmg = 2m x a
mg (1 space minus 2 straight mu) = 3m x a
straight a space equals space 2 over 3 left parenthesis 1 minus 2 straight mu right parenthesis