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Units And Measurement

Question
CBSEENPH11020547
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The dimensions of left parenthesis straight mu subscript straight o straight epsilon subscript straight o right parenthesis to the power of negative 1 divided by 2 end exponent are

  • [L1/2 T-1/2]

  • [L-1T]

  • [LT-1]

  • [L1/2 T1/2]

Solution
Multi-choise Question

C.

[LT-1]

left parenthesis straight mu subscript straight o straight epsilon subscript straight o right parenthesis to the power of negative 1 divided by 2 end exponent space is space velocity space of space light
Hence space straight c space equals space fraction numerator 1 over denominator square root of straight mu subscript straight o straight epsilon subscript straight o end root end fraction space equals space left square bracket LT to the power of negative 1 end exponent right square bracket

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Can we use different units to measure same physical quantity?

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