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Mechanical Properties Of Fluids

Question
CBSEENPH11020546

A uniform rope of length L and mass m1 hangs vertically from a rigid support. A block of mass m2 is attached to the free end of the rope. A transverse pulse of wavelength straight lambda subscript 1 is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is straight lambda subscript 2. The ratio straight lambda subscript 2 over straight lambda subscript 1 is,

  • square root of fraction numerator straight m subscript 1 plus straight m subscript 2 over denominator straight m subscript 2 end fraction end root
  • square root of straight m subscript 2 over straight m subscript 1 end root
  • square root of fraction numerator straight m subscript 1 plus straight m subscript 2 over denominator straight m subscript 1 end fraction end root
  • square root of straight m subscript 1 over straight m subscript 2 end root

Solution

A.

square root of fraction numerator straight m subscript 1 plus straight m subscript 2 over denominator straight m subscript 2 end fraction end root

Wavelength of the transverse pulse is,
straight lambda space equals space straight nu over straight f            ... (i);
where v is the velocity of the wave and f is the frequency of the wave.
We know that,

straight nu space equals space square root of straight T over straight mu end root space space space space space space space space space space space space space... space left parenthesis ii right parenthesis
T is the tension in the spring
straight mu is the mass per unit length of the rope
From eqns. (i) and (ii), we have

space space space space space straight lambda space equals space 1 over straight f square root of straight T over straight mu end root
rightwards double arrow space straight lambda space proportional to space square root of straight T
For two different cases, we have
straight lambda subscript 2 over straight lambda subscript 1 space equals square root of T subscript 2 over T subscript 1 end root
space space space space space space equals space square root of fraction numerator m subscript 1 plus m subscript 2 over denominator m subscript 2 end fraction end root