Question
A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 15 S, then
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S=ft
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S= ft2/72
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S = 1/2 ft2
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S = 1/4 ft2
Solution
B.
S= ft2/72

