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Motion In A Plane

Question
CBSEENPH11020432

The relation between time t and distance x is t=ax2 +bx where a and b are constants. The acceleration is

  • −2abv2

  • 2bv3

  • −2av3

  • 2av2

Solution

C.

−2av3

 if t = ax2+bx
then, differentiate both side with respect to time (t)
 
dtdt = 2axdxdt +bdxdt1 = 2axv +bvv.(2ax + b) = 1(2ax + b) = 1/v
 
Again differentiate both side with respect to time (t)
2adxdt = -v2.dvdt2av = - v-2.accelerationacceleration = -2av3
Hence, retardation= -2av3