A whistle producing sound waves of frequencies 9500 Hz and above is approaching a stationary person with speed v ms⁻¹. The velocity of sound in air is 300 ms−1. If the person can hear frequencies upto a maximum of 10,000 Hz, the maximum value of v upto which he can hear the whistle is

$15 square root of 2 space ms to the power of negative 1 end exponent$
$15 divided by square root of 2 space ms to the power of negative 1 end exponent$

15 ms^-1

30 ms^-1

Solution

15 ms^-1

straight f subscript app space equals space fraction numerator straight f left parenthesis 300 right parenthesis over denominator 300 minus straight v end fraction rightwards double arrow space straight v space equals space 15 space straight m divided by straight s

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