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Thermal Properties Of Matter

Question
CBSEENPH11020497
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Time taken by a 836 W heater to heat one litre of water from 10°C to 40°C is

  • 50 s

  • 100 s

  • 150 s

  • 200 s

Solution

C.

150 s

Let time taken in boiling the water by the heater is t sec. Then
Q = ms ∆ T
fraction numerator 836 space over denominator 4.2 end fraction straight t space equals space 1 space straight x space 1000 space left parenthesis 40 to the power of 0 minus 10 to the power of 0 right parenthesis fraction numerator 836 over denominator 4.2 end fraction space straight t space equals space 1000 space straight x space 30 space straight t space equals space fraction numerator 1000 space space straight x space 30 space straight x space 4.2 over denominator 836 end fraction space equals space 150 space straight s

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