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Gravitation

Question
CBSEENPH11020479

If g is the acceleration due to gravity on the earth’s surface, the gain in the potential energy of object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is

  • 2 mgR

  • mgR/2

  • mgR/4

  • mgR

Solution

B.

mgR/2

Gravitational potential energy of body on earth's surface
straight U space equals space minus space fraction numerator GM subscript straight e straight m over denominator straight R end fraction
At a height h from earth's surface, its value is
straight U subscript straight h space equals space minus space fraction numerator GM subscript straight e straight m over denominator left parenthesis straight R plus straight h right parenthesis end fraction
space equals space fraction numerator GM subscript straight e straight m over denominator 2 straight R end fraction
where Me = mass of earth
m = mass of body
R = radius of earth
therefore comma space Gain space in space potential space energy space equals space straight U subscript straight h minus straight U
equals space fraction numerator negative space GM subscript straight e straight m over denominator 2 straight R end fraction minus open parentheses fraction numerator GM subscript straight e straight m over denominator straight R end fraction close parentheses
space equals space fraction numerator GM subscript straight e straight m over denominator 2 straight R end fraction space plus space fraction numerator GM subscript straight e straight m over denominator straight R end fraction
space equals space fraction numerator GM subscript straight e straight m over denominator 2 straight R end fraction
space equals space fraction numerator gR squared straight m over denominator 2 straight R end fraction space space open parentheses straight g space equals space GM subscript straight e over straight R close parentheses
space equals space 1 half space mgR