A force $straight F with rightwards arrow on top space equals space left parenthesis 5 straight i with hat on top space plus 3 straight j with hat on top space plus 2 straight k with hat on top right parenthesis space straight N$ is applied over a particle which displaces it from its origin to the $straight r with rightwards arrow on top space equals space left parenthesis 2 straight i with hat on top minus straight j with hat on top right parenthesis space straight m$ .The work done on the particle in joules is

-7

+7

+10

+13

Solution

Work done in displacing the particle
$straight W space equals space straight F with rightwards arrow on top space. straight r with rightwards arrow on top space equals space left parenthesis 5 straight i with hat on top space plus space 3 straight j with hat on top space plus 2 straight k with hat on top right parenthesis. left parenthesis 2 straight i with hat on top space minus straight j with hat on top right parenthesis space equals space 5 space straight x space 2 space plus 3 space straight x space left parenthesis negative 1 right parenthesis space plus space 2 straight x 0 space equals space 10 minus 3 equals space 7 straight J$

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Work, Energy And Power

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