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Laws Of Motion

Question
CBSEENPH11020468

A machine gun fires a bullet of mass 40 g with a velocity 1200 ms−1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?

  • one 

  • Four

  • Two

  • Three

Solution

D.

Three

The force exerted by machine gun on man's hand in firing a bullet = change in momentum per second on a bullet or rate of change of momentum
space equals open parentheses 40 over 1000 close parentheses space straight x space 1200 space equals space 48 space straight N
The force exerted by man on machine gun = 144 N Hence, number of bullets fired =144/48 = 3