Sponsor Area

Gravitation

Question
CBSEENPH11020449

A particle of mass 10 g is kept on the surface of a uniform sphere of mass 100 kg and radius 10 cm. Find the work to be done against the gravitational force between
(you may take G = 6 . 67× 10-11 Nm2/ kg2)

  • 13.34 x 10-10 J

  • 3.33 x 10-10 J

  • 6.67 x10-9 J

  • 6.67 x10-10 J

Solution

D.

6.67 x10-10 J

increment straight W space equals space straight v subscript straight f minus straight v subscript straight i
space equals space 0 minus open square brackets fraction numerator negative GMm over denominator straight R end fraction close square brackets
straight w space equals space fraction numerator space 6.67 space straight x space 10 to the power of negative 11 end exponent space space straight x 1000 over denominator.1 end fraction space straight x 10 over 1000 space equals space 6.67 space straight x space 10 to the power of negative 10 space end exponent straight J