Question

The equation of a wave on a string of linear mass density 0.04 kg m^–1 is given by y= 0.02(m) sin $open square brackets 2 straight pi open parentheses fraction numerator straight t over denominator 0.04 space left parenthesis straight s right parenthesis end fraction minus fraction numerator straight x over denominator 0.50 space left parenthesis straight m right parenthesis end fraction close parentheses close square brackets$ The tension in the string is

4.0 N

12.5

0.5 N

6.25 N

Solution

6.25 N

The tension in the string
on comparing with the standard equation,
y = a sin (ω t = kx)
T = μv² = μω^2/k² = 0.04
= 0.04 (2π/0.004)²/(2π/0.50)²
= 6.25

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