A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v, the total area around the fountain that gets wet is

$straight pi straight v to the power of 4 over straight g squared$
$straight pi over 2 straight v to the power of 4 over straight g squared$
$straight pi straight v squared over straight g squared$
$straight pi straight v squared over straight g$

Solution

straight pi straight v squared over straight g squared

Maximum range of water coming out of the fountain
$straight R subscript straight m space equals space straight v squared over straight g therefore comma space Total space area space around space fountain space straight A space equals space πR subscript straight m superscript 2 space equals straight pi straight v to the power of 4 over straight g squared$