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Mechanical Properties Of Fluids

Question
CBSEENPH11020320

A mass M, attached to a horizontal spring, executes SHM with an amplitude A1. When the mass M passes through its mean position than a smaller mass m is placed over it and both of them move together with amplitude A2. The ratio of (A1/A2) is

  • fraction numerator straight M space plus straight m over denominator straight M end fraction
  • open parentheses fraction numerator straight M over denominator straight M plus straight m end fraction close parentheses to the power of 1 divided by 2 end exponent
  • fraction numerator straight M over denominator straight M plus straight m end fraction

Solution

C.

At mean position, Fnet = 0
Therefore, By conservation of linear momentum,
Mv1 = (M+m)v2
1A1 = (M+m)ω2A2
⇒ rightwards double arrow space open parentheses fraction numerator straight M over denominator straight M plus straight m end fraction close parentheses space equals space fraction numerator straight omega subscript 2 straight A subscript 2 over denominator straight omega subscript 1 straight A subscript 1 end fraction
But space straight omega subscript 1 space equals space square root of straight k over straight M end root space and space straight omega subscript 2 space equals space square root of fraction numerator straight k over denominator straight M plus straight m end fraction end root
On space solving comma space we space get space straight A subscript 1 over straight A subscript 2 space equals space square root of fraction numerator straight m plus straight M over denominator straight M end fraction end root