A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R.Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass m, if the string does not slip on the pulley, is

g

2/3g

g/3

3/2g

Solution

2/3g

mg - T = ma

TR space equals space fraction numerator mR squared straight alpha over denominator 2 end fraction straight T space equals space mRα over 2 space equals space ma over 2 mg space minus ma over 2 space equals space ma fraction numerator 3 space ma over denominator 2 end fraction space equals space mg straight a space equals space fraction numerator 2 straight g over denominator 3 end fraction

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