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System Of Particles And Rotational Motion

Question
CBSEENPH11020397
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A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumferences of the discs coincide. The centre of mass of the new disc is α/R from the centre of the bigger disc.The value of α is

  • 1/3

  • 1/2

  • 1/6

  • 1/4

Solution

A.

1/3

In this question distance of centre of mass of new disc is αR not α/R.

negative fraction numerator 3 straight M over denominator 4 end fraction space straight alpha space straight R space plus space straight M over 4 space straight R space equals 0 rightwards double arrow space straight alpha space equals space 1 third

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