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Motion In A Plane

Question
CBSEENPH11020352

A time-dependent force F = 6t acts on a particle of mass 1 kg. If the particle starts from rest, the work done by the force during the first 1 sec. will be

  • 9J

  • 18 J

  • 4.5 J

  • 22 J

Solution

C.

4.5 J

F = 6t = ma
⇒ a = 6t
rightwards double arrow space dv over dt space equals space 6 straight t
integral subscript 0 superscript straight v dv space equals space integral subscript 0 superscript 1 6 straight t space dt
straight v space equals space left parenthesis 3 straight t squared right parenthesis subscript 0 superscript 1 space equals space 3 space straight m divided by straight s
from space work space energy space theorem
straight W subscript straight F space equals space increment straight K. straight E space equals space 1 half straight m space left parenthesis straight v squared minus straight u squared right parenthesis
space equals space 1 half left parenthesis 1 right parenthesis left parenthesis 9 minus 0 right parenthesis space equals space 4.5 straight J