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Mechanical Properties Of Fluids

Question
CBSEENPH11020217

You are riding in an automobile of mass 3000 kg. Assuming that you are examining the oscillation characteristics of its suspension system. The suspension sags 15 cm when the entire automobile is placed on it. Also, the amplitude of oscillation decreases by 50% during one complete oscillation. Estimate the values of (a) the spring constant and (b) the damping constant for the spring and shock absorber system of one wheel, assuming that each wheel supports 750 kg.

Solution
(a)
Mass of the automobile, m = 3000 kg
Displacement in the suspension system, x = 15 cm = 0.15 m
There are 4 springs in parallel to the support of the mass of the automobile.
The equation for the restoring force for the system:
 
                       F = –4kx = mg 

where,
is the spring constant of the suspension system
Time period, T = 2π √m/4k

Spring constant, k = mg/4x 
                        = 3000 × 10/ 4 × 0.15
                        = 5000
                        = 5 × 104 Nm 
Spring Constant, = 5 × 104 Nm
(b) Each wheel supports a mass, M = 3000/4 = 750 kg 
For damping factor b, the equation for displacement is written as
x = x0e-bt/2M

The amplitude of oscilliation decreases by 50 %. 
∴  x = x0/2 
x0/2 = x0e-bt/2M

loge2 = bt/2

Therefore,
     b = 2loge2 / t
where,

Time space Period comma space straight T space equals space 2 straight pi space square root of fraction numerator straight m over denominator 4 straight k end fraction end root space

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therefore space straight b space equals space fraction numerator 2 space straight x space 750 space straight x 0.693 over denominator 0.7691 end fraction space equals space 1351. space 58 space kg divided by straight s