+91-8076753736 [email protected]

-->

Mechanical Properties Of Fluids

Question

Wired Faculty App

The acceleration due to gravity on the surface of the moon is 1.7 ms^–2. What is the time period of a simple pendulum on the surface of the moon if its time period on the surface of Earth is 3.5 s? (g on the surface of earth is 9.8 ms^–2)

Solution

Acceleration due to gravity on the surface of moon, g' = 1.7 m s^–2

Acceleration due to gravity on the surface of earth, g = 9.8 m s^–2
Time period of a simple pendulum on earth, T = 3.5 s

Error converting from MathML to accessible text.

Hence, the time period of the simple pendulum on the surface of the moon is 8.4 sec.

Some More Questions From Mechanical Properties of Fluids Chapter

Is there any relation between uniform circular motion and simple harmonic motion?

What is periodic motion?

Write down the expression for the instantaneous velocity and acceleration of particle vibrating in simple harmonic motion.

How do you define the mean position of particle executing simple harmonic motion?

Define amplitude.

What is the net displacement of the particle executing simple harmonic motion in one complete oscillation?

Are all the periodic motions simple harmonic?

Does the time period of particle vibrating in simple harmonic motion depend upon its displacement?

Where will the particle executing simple harmonic motion have acceleration maximum and speed zero?

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation