Question
A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?
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A meter scale.
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A vernier calliper where the 10 divisions in vernier scale match with 9 division in the main scale and main scale have 10 divisions in 1 cm.
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A screw gauge having 100 divisions in the circular scale and pitch as 1 mm.
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A screw gauge having 100 divisions in the circular scale and pitch as 1 mm.
Solution
B.
A vernier calliper where the 10 divisions in vernier scale match with 9 division in the main scale and main scale have 10 divisions in 1 cm.
If student measures 3.50 cm, it means that there is an uncertainty of order 0.01 cm
For vernier scale with 1 MSD = 1mm
and 9 MSD = 10 VSD
LC of vernier scale with 1 MSD - 1 VSD
