A pipe of length 85 cm is closed from one end. Find the number of possible natural oscillations of the air column in the pipe whose frequencies lie below 1250 Hz. The velocity of sound in air is 340 m/s.

12

8

6

4

Solution

i.e,

straight lambda over 4 space equals space 0.85 rightwards double arrow straight lambda space 4 space straight x space 0.85 As space we space know comma space straight v space equals space straight c over straight lambda rightwards double arrow space fraction numerator 340 over denominator 4 space straight x space 0.85 end fraction space equals space 100 space Hz

therefore, possible frequencies = 100 Hz, 300 Hz, 500 Hz, 700Hz, 900Hz, 1100Hz, below 1250 Hz.

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