Question
Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion the average time of collision between molecules increases as Vq , where V is the volume of the gas. The value of q is: 
Solution
C.
For an adiabatic process TVγ-1 = constant
We know that average time of collision between molecules
Where n= number of molecules per unit volume
vrms = rms velocity of molecules
Thus, we can write
n =K1V-1 and Vrms = K2T1/2
Where K1 and K2 are constants.
For adiabatic process TVγ-1 = constant. Thus we can write
