Question
A solid cylinder rolls up an inclined plane of angle of inclination 30°. At the bottom of the inclined plane the centre of mass of the cylinder has a speed of 5 m/s.
(a) How far will the cylinder go up the plane?
(b) How long will it take to return to the bottom?
(b) How long will it take to return to the bottom?
Solution
Initial velocity of the solid cylinder, v = 5 m/s
Angle of inclination, θ = 30°
Let the cylinder go up the plane upto a height h.
Using the relation, Angle of inclination, θ = 30°
Let the cylinder go up the plane upto a height h.


If s is the distance up the inclined plane, then as
sin θ =

s =

=

Therefore, time taken to return to the bottom of the inclined plane,

1.53 sec is required for the balloon to return to the bottom.