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Units And Measurement

Question
CBSEENPH11020121

Show that the area of the triangle contained between the vectors a and b is one half of the magnitude of a × b.

Solution
Consider two vectors OK = vector |a| and OM = vector |b|, inclined at an angle θ, as shown in the following figure.

                           
In space increment space OMN comma space using space the space relation comma space

sin space straight theta space equals space MN over OM space equals space fraction numerator MN over denominator open vertical bar straight b with rightwards harpoon with barb upwards on top close vertical bar end fraction

space space MN space equals space open vertical bar straight b with rightwards harpoon with barb upwards on top close vertical bar space sin space straight theta

open vertical bar straight a with rightwards harpoon with barb upwards on top space straight x space straight a with rightwards harpoon with barb upwards on top close vertical bar space equals space open vertical bar straight a with rightwards harpoon with barb upwards on top close vertical bar space open vertical bar straight b with rightwards harpoon with barb upwards on top close vertical bar space sin space straight theta space

space space space space space space space space space space space space space space space equals space OK space straight x space MN space straight x space 2 over 2

space space space space space space space space space space space space space space space equals space 2 space straight x space Area space of space increment space OMK space

therefore space space Area space of space increment space OMK space equals space 1 half space open vertical bar straight a with rightwards harpoon with barb upwards on top space straight x space straight b with rightwards harpoon with barb upwards on top close vertical bar 
Area of the triangle contained between the vectors a and b is one-half of the magnitude of a x b