Question
A body of mass 0.5 kg travels in a straight line with velocity v = ax3/2 where a = 5 m -1/2 s-1. What is the work done by the net force during its displacement from x = 0 to x= 2 m?
Solution
Given,
Mass of the body, m = 0.5 kg
Velocity of the body is governed by the equation,Mass of the body, m = 0.5 kg
v = ax3/2
Acceleration, a = 5 m -1/2 s-1
Initial velocity, u (at x = 0) = 0
Final velocity v (at x = 2 m) = 10√2 m/s
Work done, W = Change in kinetic energy
= (
) m (v2 - u2) = (
) × 0.5 [ (10√2)2 - 02]= (
) × 0.5 × 10 × 10 × 2= 50 J
