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Mechanical Properties Of Fluids

Question
CBSEENPH11020189

From a certain apparatus, the diffusion rate of hydrogen has an average value of 28.7 cm3 s–1. The diffusion of another gas under the same conditions is measured to have an average rate of 7.2 cm3 s–1. Identify the gas.
[Hint: Use Graham’s law of diffusion: R1/R2 = (M2/M1)1/2, where R1, R2 are diffusion rates of gases 1 and 2, and M1and M2 their respective molecular masses. The law is a simple consequence of kinetic theory.]

Solution
Rate of diffusion of hydrogen, R= 28.7 cm3 s–1
Rate of diffusion of another gas, R2 = 7.2 cm3 s–1 

According to Graham’s Law of diffusion, we have
straight R subscript 1 over straight R subscript 2 space equals space square root of M subscript 2 over M subscript 1 end root space

w h e r e comma space

M subscript 1 space i s space t h e space m o l e c u l a r space m a s s space o f space h y d r o g e n space equals space 2.020 space g space

M subscript 2 space i s space t h e space m o l e c u l a r space m a s s space o f space t h e space u n k n o w n space g a s

T h e r e f o r e comma space

M subscript 2 space equals space M subscript 1 space open parentheses R subscript 1 over R subscript 2 close parentheses squared space

space space space space space equals space 2.02 space x space open parentheses fraction numerator 28.7 over denominator 7.2 end fraction close parentheses squared space

space space space space space equals space 32.09 space g
32 g is the molecular mass of oxygen. Hence, the unknown gas is oxygen.