+91-8076753736 support@wiredfaculty.com
logo
logo

Sponsor Area

Mechanical Properties Of Fluids

Question
CBSEENPH11020183
Wired Faculty App

An air bubble of volume 1.0 cm3 rises from the bottom of a lake 40 m deep at a temperature of 12 °C. To what volume does it grow when it reaches the surface, which is at a temperature of 35 °C?

Solution
Volume of the air bubble, V1 = 1.0 cm3 = 1.0 × 10–6 m3 

Bubble rises to height, d = 40 m 
Temperature at a depth of 40 m, T1 = 12°C = 285 K 
Temperature at the surface of the lake, T2 = 35°C = 308 K 
The pressure on the surface of the lake, 
P2 = 1 atm = 1 ×1.013 × 105 Pa
The pressure at the depth of 40 m, 
P1 = 1 atm + dρg 
where, 
ρ is the density of water = 103 kg/m3 

g is the acceleration due to gravity = 9.8 m/s2 

Therefore, 
P1 = 1.013 × 105 + 40 × 103 × 9.8
     = 493300 Pa 
We have,
 P1V1 / T1 = P2V2 / T2 

where,
 V2 is the volume of the air bubble when it reaches the surface. 
V2 = P1V1T2 / T1P2 

      = 493300 × 1 × 10-6 × 308 / (285 × 1.013 × 105) 
      = 5.263 × 10–6 m3 
 
       = 5.263 cm3 

Therefore, when the air bubble reaches the surface, its volume becomes 5.263 cm3.

Some More Questions From Mechanical Properties of Fluids Chapter

What are different types of wave motions?

Define transverse wave motion.

Define longitudinal wave motion.

Which of the two waves - elastic waves or electromagnetic waves does need any material media for its propagation?

What is sound?

How sound is produced?

Can sound travel in vacuum?

Can two persons hear each other on the moon? Explain.

Can electromagnetic wave propagate in vacuum?

Can we listen in vacuum?

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation