A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g^–1K^–1; heat of fusion of water = 335 J g^–1).

Solution

Given that,
Mass of the copper block, m = 2.5 kg = 2500 g
Rise in the temperature of the copper block, Δθ = 500°C
Specific heat of copper, C = 0.39 J g^–1°C^–1
Heat of fusion of water, L = 335 J g^–1
The maximum heat the copper block can lose, Q = mCΔθ

= 2500 × 0.39 × 500
= 487500 J
Let m₁ g be the amount of ice that melts when the copper block is placed on the ice block.
The heat gained by the melted ice, Q = m₁L

∴ m₁ = Q / L
= 487500 / 335
= 1455.22 g
Hence, the maximum amount of ice that can melt is 1.45 kg.

Some More Questions From Mechanical Properties of Fluids Chapter

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Mechanical Properties Of Fluids

A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g^–1K^–1; heat of fusion of water = 335 J g^–1).

Some More Questions From Mechanical Properties of Fluids Chapter

What determines the natural frequency of an oscillator?

Is there any relation between uniform circular motion and simple harmonic motion?

What is periodic motion?

Write down the expression for the instantaneous velocity and acceleration of particle vibrating in simple harmonic motion.

How do you define the mean position of particle executing simple harmonic motion?

Define amplitude.

What is the net displacement of the particle executing simple harmonic motion in one complete oscillation?

Are all the periodic motions simple harmonic?

Does the time period of particle vibrating in simple harmonic motion depend upon its displacement?

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Mechanical Properties Of Fluids

A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g–1 K–1; heat of fusion of water = 335 J g–1).

Some More Questions From Mechanical Properties of Fluids Chapter

What determines the natural frequency of an oscillator?

Is there any relation between uniform circular motion and simple harmonic motion?

What is periodic motion?

Write down the expression for the instantaneous velocity and acceleration of particle vibrating in simple harmonic motion.

How do you define the mean position of particle executing simple harmonic motion?

Define amplitude.

What is the net displacement of the particle executing simple harmonic motion in one complete oscillation?

Are all the periodic motions simple harmonic?

Does the time period of particle vibrating in simple harmonic motion depend upon its displacement?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g^–1K^–1; heat of fusion of water = 335 J g^–1).