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Laws Of Motion

Question
CBSEENPH11020063

A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms–1. How long does the body take to stop?

Solution

Retarding Force, F = - 50 N
Mass of the body, m = 20 kg 
Initial velocity of the body, u = 15 m/s
Final velocity of the body, v = 0 
Acceleration produced in the body can be calculated as: 
   F = ma
-50 = 20 x a
  a = fraction numerator negative 50 over denominator space 20 end fraction space equals space minus 2.5 space m divided by s squared
Using the first equation of motion,

                          v = u + at 
Time (t) taken by the body to come to rest can be calculated as,

Therefore,
                 t = negative straight u over straight a space equals space fraction numerator negative 15 over denominator negative 2.5 end fraction space equals space 6 space s