Question
A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm2. What maximum pressure would the smaller piston has to bear?
Solution
Area of cross-section of the piston, A = 425 cm2 = 4.25 
Maximum load on piston, F = 3000 kg = 3000 X 9.8 N
Therefore,
Maximum pressure on the piston on which car is, 
