Mechanical Properties of Fluids

Question

What is the density of water at a depth where pressure is 80.0 atm, given that its density at the surface is 1.03 × 10³kg m^–3?

Solution

Let the given depth be h.
Pressure at the given depth, p = 80.0 atm = 80 × 1.01 × 10⁵Pa
Density of water at the surface, ρ₁= 1.03 × 10³ kg m^–3
Let ρ₂ be the density of water at the depth h.
Let V₁ be the volume of water of mass m at the surface.
Let V₂ be the volume of water of mass m at the depth h.
Let ΔV be the change in volume.
ΔV = V₁ - V_{2
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