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Motion In A Plane

Question
CBSEENPH11019950

An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900
km/h. Compare its centripetal acceleration with the acceleration due to gravity

Solution
Radius of the loop, r = 1 km = 1000 m 
Speed of the aircraft, v = 900 km/h = 900 × 5 / 18  =  250 m/s
Centripetal acceleration, straight a subscript straight c space equals space straight v squared over straight r
fraction numerator left parenthesis 250 right parenthesis squared over denominator 1000 end fraction space equals space 62.5 space m divided by s squared
Acceleration due to gravity, g = 9.8 m/s2
Therefore, 

ac / g = 62.5 / 9.8  =  6.38
ac = 6.38 g, is the required centripetal acceleration.