The photograph of a house occupies an area of 1.75 cm²on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m². What is the linear magnification of the projector-screen arrangement.

Solution

Area space of space the space house space on space the space slide space equals space 1.75 space cm squared space Area space of space the space image space of space the space house space formed space on space the space screen space equals space 1.55 space straight m squared space equals space 1.55 cross times 10 to the power of 4 space cm squared space Therefore comma space Arial space magnification comma space straight m subscript straight a space equals space fraction numerator Area space of space image over denominator Area space of space object end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 1.55 over denominator 1.75 end fraction cross times space 10 to the power of 4 space So comma space linear space magnification comma space straight m subscript straight l space equals square root of straight m subscript straight a end root space equals space square root of fraction numerator 1.55 over denominator 1.75 end fraction cross times space 10 to the power of 4 space end root space equals space 94.11 space

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