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Mechanical Properties Of Fluids

Question
CBSEENPH11019856
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Calculate the molecular kinetic energy of 1 gram of helium( molecular weight 4) at 127°C.

R= 8.31 J 

Solution

Here, we have
M = 4 
T = 127 + 273 
R =8.31 J mole-1 K-1
Average K.E per mole of helium = 3 over 2 space R space T

Average K.E of 1 g of helium = 3 over 2 fraction numerator R T over denominator M end fraction 
               = fraction numerator 3 cross times 8.31 cross times 400 over denominator 2 cross times 4 end fraction space equals space 1246.5 space J

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