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Mechanical Properties Of Fluids

Question
CBSEENPH11019846

From the data given below calculate the black body temperature of the sun:
straight sigma equals 5.67 cross times 10 to the power of negative 8 end exponent straight J divided by straight m squared sK to the power of 4 space space space space space space space space space space space space space space space straight S equals 1340 space straight J divided by straight m squared straight s
Radius of the sun = 7 cross times 10 to the power of 8 straight m
Radius of the earth's obrit equals 1.5 cross times 10 to the power of 11 straight m

Solution

The surface temperature of sun is given by, 
                  straight T equals fourth root of fraction numerator straight R squared straight S over denominator σr squared end fraction end root 
Putting the values, we get 
                Temperature comma space straight T equals fourth root of fraction numerator left parenthesis 1.5 cross times 10 to the power of 11 right parenthesis squared 1340 over denominator left parenthesis 5.67 cross times 10 to the power of negative 8 end exponent right parenthesis left parenthesis 7 cross times 10 to the power of 8 right parenthesis squared end fraction end root space

space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 570 straight K