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Mechanical Properties Of Fluids

Question
CBSEENPH11019838

Find the rate of energy radiated by a black body of radius 2.1 cm when heated at temperature 600K.
Take space space space space straight sigma equals 5.67 cross times 10 to the power of negative 8 end exponent Wm to the power of negative 2 end exponent straight K to the power of negative 4 end exponent
            
                 
            
         

Solution
Energy radiated per second by black body is given by, 
                       space space space space space space space space straight E equals σAT to the power of 4 
Given that,
Stefan apostrophe straight s space constant comma space straight sigma space equals space 5.67 cross times 10 to the power of negative 8 end exponent Wm to the power of negative 2 end exponent straight K to the power of negative 4 end exponentArea space of space the space balck space body comma space straight A equals 4 πr squared equals 4 straight pi left parenthesis 2.1 right parenthesis squared cross times 10 to the power of negative 4 end exponent straight m squared space

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 5.544 cross times 10 to the power of negative 3 end exponent straight m squared
Temperature comma space straight T space equals space 600 straight K
Therefore, 
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               equals 40.74 space straight J divided by straight s 
This is the rate of energy radiated by a black body when heated at a temperature of 600 K.