A shivering man wraps himself in flannel coat of thickness 4mm in winter when the temperature of the day is 12°C. The total surface area of man is 1.5m². Find the rate of lose of heat by his body. The temperature of the body is 37°C and thermal conductivity of flannel is 0.0012 cal/m/°C/s.

Solution

W e space h a v e comma space space space space space space space space space space space space space space space space space space space space space space space space space space fraction numerator d Q over denominator d t end fraction equals straight K fraction numerator A theta over denominator straight l end fraction space H e r e comma T h e r m a l space c o n d u c t i v i t y comma space straight K space equals space 0.0012 space c a l divided by straight m divided by degree straight C divided by straight s space T e m p e r a t u r e space d i f f r e n c e comma space straight theta equals 37 minus 12 equals 25 degree straight C comma S. A space o f space m a n comma space straight A equals 1.5 straight m squared Thickness space of space flannel comma space straight ell equals 4 m m equals 4 cross times 10 to the power of negative 3 end exponent straight m therefore space space space space space space fraction numerator d Q over denominator d t end fraction equals 0.0012 fraction numerator 1.5 cross times 25 over denominator 4 cross times 10 to the power of negative 3 end exponent end fraction space space space space space space space space space space space space space space space space space space space equals 11.25 space c a l divided by straight s

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