Question
Three moles of helium gas are initially at 300K and occupy a volume of 25 liters. The gas is first expanded at constant pressure until volume is increased to 60 liters. Then it undergoes an adiabatic expansion until the temperature decreases to 400K. Find the work done by the gas during adiabatic expansion.
Solution
Let P, V and T be the initial pressure, volume and temperature.
Let P', V' and T' be the pressure, volume and temperature after isobaric expansion.
We have,
Temperature, T = 300K
Using the perfect gas equation for an isochoric process.
Now the gas is expanded adiabatically.
Therefore, the work done by gas during adiabatic expansion is,
Given here,
So, work done by the gas during adiabatic expansion is,
∴![<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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Let P', V' and T' be the pressure, volume and temperature after isobaric expansion.
We have,
Temperature, T = 300K
Using the perfect gas equation for an isochoric process.
Now the gas is expanded adiabatically.
Therefore, the work done by gas during adiabatic expansion is,
Given here,
So, work done by the gas during adiabatic expansion is,
∴
