Question
An ideal gas is taken through as shown in figure. Find the work done by gas in the process
What is the net heat absorbed by the gas in cyclic process?
Solution
The magnitude of area under CA curve on PV diagram is,
Area = Area of trapezium ACcaA
In the process
the gas gets compressed.
Therefore, work done by gas is negative.
Thus,
Now by the first law of thermodynamics for cyclic process,
= Area of rectangle AbcaA + 0 + (-5.5)
= 10(2 - 1) -5.5 = 4.5J
Thus the heat absorbed by gas in the cyclic process is 4.5J.
Area = Area of trapezium ACcaA
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In the process

Therefore, work done by gas is negative.
Thus,

Now by the first law of thermodynamics for cyclic process,



= Area of rectangle AbcaA + 0 + (-5.5)
= 10(2 - 1) -5.5 = 4.5J
Thus the heat absorbed by gas in the cyclic process is 4.5J.