-->

Mechanical Properties Of Fluids

Question
CBSEENPH11019622

One gram of water at 100°C and 1 atmospheric pressure is boiled and converted into steam. The one gm of water occupies volume 1cc and steam occupies the volume 1671cc. Find the work done and increase in internal energy of water. The latent heat of vaporisation is 540 cal/gm.

Solution

The amount of work done to convert 1 gram water into steam at 1 atmospheric pressure is given by, 
increment straight W space equals space straight P space left parenthesis straight V subscript steam space minus space straight V subscript water right parenthesis space

Here comma space we space have

Pressure comma space straight P space equals space 1.01 space cross times space 10 to the power of 5 space straight N divided by straight m squared space comma space and space

straight V subscript steam space end subscript space minus space straight V subscript water space end subscript space equals space left parenthesis 1671 space minus space 1 right parenthesis thin space cc space

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1.670 space cross times space 10 to the power of negative 3 end exponent space straight m cubed space
Therefore comma space

increment straight W space equals space 1.01 space cross times space 10 to the power of 5 space cross times space 1.670 space cross times 10 to the power of negative 3 end exponent space straight J

space space space space space space space space space equals space 168.67 space straight J space equals space 40 space Cal space

Using space the space first space law space of space thermodynamics comma space

increment straight U space equals space increment straight Q space minus space increment straight W space

space space space space space space space space equals space mL space minus space increment straight W space

space space space space space space space space equals space 1 space cross times 540 space minus space 40 space equals space 500 space Cal space
Therefore, the internal energy increases by 500 Cal.