Question
In an industrial process 10 kg of water per hour is to be heated from 20°C to 80°C. For this, steam at 160°C from boiler is passed in the coil dipped in water. The steam condenses and returns back to boiler at 95°C. How many kg of steam are required per hour? Take specific heat of steam 2 cal/gm/K.
Solution
Let m gm of steam be required per hour to raise the temperature of water.
The formula of calorimetry is given by,
Q =
where,
q is the amount of heat transferred,
c is the specific heat of the substance,
m is the mass of the substance, and
is the temperature change.
= Tf - Ti
Now, according to the law of calorimetry, we have
Heat lost by steam = Heat gained by water
m x 2 x 60 + m x 540 + m x 1 x 5 = 10,000 x 1 x 60
665 m = 60, 000
m = 902.26 gm, is the mass of steam required per hour.
The formula of calorimetry is given by,
Q =
where,
q is the amount of heat transferred,
c is the specific heat of the substance,
m is the mass of the substance, and
is the temperature change. = Tf - TiNow, according to the law of calorimetry, we have
Heat lost by steam = Heat gained by water
m x 2 x 60 + m x 540 + m x 1 x 5 = 10,000 x 1 x 60
665 m = 60, 000 m = 902.26 gm, is the mass of steam required per hour.
